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This Python program tells the user whether the entered year is leap year or not. Seems Simple, But its a bit dicey..Give it a Try!!
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while True:
a = int(input("Enter year : "))
if a % 100 == 0:
if a % 400 == 0:
print("The year is leap")
else:
print("Not a leap Year")
else:
if a % 4 == 0:
print("The year is leap")
else:
print("No leap")
